What is the answer to 3/2 log_{27}(x+5)=1 ?

The answer to 3/2 log_{27}(x+5)=1 is x=4

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3/2 log_{27}(x+5)=1

\frac{3}{2} lo g_{27} (x + 5) = 1

x = 4

Solution steps

\frac{3}{2} lo g_{27} (x + 5) = 1

Multiply both sides by

2

3 lo g_{27} (x + 5) = 2

Divide both sides by

3

lo g_{27} (x + 5) = \frac{2}{3}

Apply log rules

x + 5 = 9

Solve

x + 5 = 9 : x = 4

x = 4

Verify Solutions:

x = 4

True

The solution is

x = 4

y, ln (y) = x^{2}

lo g_{2} (3 x - 4) = 3

lo g_{4} (x + 4) + lo g_{4} (x - 2) = 2

lo g_{x} (64) = \frac{3}{4}

ln (x^{2}) = 9

What is the answer to 3/2 log_{27}(x+5)=1 ?
The answer to 3/2 log_{27}(x+5)=1 is x=4
Solve for x: 3/2 log_{27}(x+5)=1
The solution is x=4