What is the answer to ln(4-x)-ln(x+1)=ln(2) ?

The answer to ln(4-x)-ln(x+1)=ln(2) is x= 2/3

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ln(4-x)-ln(x+1)=ln(2)

ln (4 - x) - ln (x + 1) = ln (2)

x = \frac{2}{3}

Decimal Notation

x = 0.66666 \dots

Solution steps

ln (4 - x) - ln (x + 1) = ln (2)

Add

ln (x + 1)

to both sides

ln (4 - x) - ln (x + 1) + ln (x + 1) = ln (2) + ln (x + 1)

Simplify

ln (4 - x) = ln (2) + ln (x + 1)

Apply log rules

4 - x = 2 (x + 1)

Solve

4 - x = 2 (x + 1) : x = \frac{2}{3}

x = \frac{2}{3}

Verify Solutions:

x = \frac{2}{3}

True

The solution is

x = \frac{2}{3}

ln (3 x + 2) + ln (x - 1) = 1

0.45 = lo g_{10} (x)

lo g_{x} (64) = 1

lo g_{10} (x) = ln (x)

lo g_{2} (2 x + 3) = lo g_{2} (x + 7)

What is the answer to ln(4-x)-ln(x+1)=ln(2) ?
The answer to ln(4-x)-ln(x+1)=ln(2) is x= 2/3
Solve for x: ln(4-x)-ln(x+1)=ln(2)
The solution is x= 2/3