What is the answer to 3+log_{2}(x)=log_{2}(x-3) ?

The answer to 3+log_{2}(x)=log_{2}(x-3) is No Solution for x\in\mathbb{R}

Solve for x: 3+log_{2}(x)=log_{2}(x-3)

The solution is No Solution for x\in\mathbb{R}

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3 + lo g_{2} (x) = lo g_{2} (x - 3)

No Solution for x \in R

Solution steps

3 + lo g_{2} (x) = lo g_{2} (x - 3)

Apply log rules

8 x = x - 3

Solve

8 x = x - 3 : x = - \frac{3}{7}

x = - \frac{3}{7}

Verify Solutions:

x = - \frac{3}{7}

False

The solution is

No Solution for x \in R

x, - ln (y) = ln (x) + c

lo g_{4} (9 x - 4) = 2

3 ln (4 x + 8) - 13 = - 22

lo g_{2} (x) - lo g_{4} (x) = 3

lo g_{2} (2 x + 1) - lo g_{2} (x - 1) = 4

What is the answer to 3+log_{2}(x)=log_{2}(x-3) ?
The answer to 3+log_{2}(x)=log_{2}(x-3) is No Solution for x\in\mathbb{R}
Solve for x: 3+log_{2}(x)=log_{2}(x-3)
The solution is No Solution for x\in\mathbb{R}