What is the answer to log_{8}(x)+log_{8}(x+12)=2 ?

The answer to log_{8}(x)+log_{8}(x+12)=2 is x=4

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log_{8}(x)+log_{8}(x+12)=2

lo g_{8} (x) + lo g_{8} (x + 12) = 2

x = 4

Solution steps

lo g_{8} (x) + lo g_{8} (x + 12) = 2

Apply log rules

x (x + 12) = 64

Solve

x (x + 12) = 64 : x = 4, x = - 16

x = 4, x = - 16

Verify Solutions:

x = 4

True

, x = - 16

False

The solution is

x = 4

lo g_{2} (x + 4) = 1 + lo g_{2} (x - 3)

ln (3 - x^{2}) = 2 ln (x)

lo g_{2} (4 x) - lo g_{2} (x^{2}) = 4

2 x \cdot ln (x) + x = 0

lo g_{2} (3 x - 1) = lo g_{4} (x + 8)

What is the answer to log_{8}(x)+log_{8}(x+12)=2 ?
The answer to log_{8}(x)+log_{8}(x+12)=2 is x=4
Solve for x: log_{8}(x)+log_{8}(x+12)=2
The solution is x=4