What is the answer to 5=-log_{1/3}(3x-5) ?

The answer to 5=-log_{1/3}(3x-5) is x= 248/3

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5=-log_{1/3}(3x-5)

5 = - lo g_{\frac{1}{3}} (3 x - 5)

x = \frac{248}{3}

Decimal Notation

x = 82.66666 \dots

Solution steps

5 = - lo g_{\frac{1}{3}} (3 x - 5)

Move

lo g_{\frac{1}{3}} (3 x - 5)

to the left side

5 + lo g_{\frac{1}{3}} (3 x - 5) = 0

Move

5

to the right side

lo g_{\frac{1}{3}} (3 x - 5) = - 5

Apply log rules

3 x - 5 = 243

Solve

3 x - 5 = 243 : x = \frac{248}{3}

x = \frac{248}{3}

Verify Solutions:

x = \frac{248}{3}

True

The solution is

x = \frac{248}{3}

lo g_{2} (- 3 x + 1) = 3

lo g_{3} (x) = 7

lo g_{\frac{1}{2}} (x) = 4

- 2 = ln (x)

1 + ln (x) = 0

What is the answer to 5=-log_{1/3}(3x-5) ?
The answer to 5=-log_{1/3}(3x-5) is x= 248/3
Solve for x: 5=-log_{1/3}(3x-5)
The solution is x= 248/3