What is the answer to 0.567=ln(x^2) ?

The answer to 0.567=ln(x^2) is x=sqrt(e^{0.567)},x=-sqrt(e^{0.567)}

Solve for x: 0.567=ln(x^2)

The solution is x=sqrt(e^{0.567)},x=-sqrt(e^{0.567)}

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0.567 = ln (x^{2})

x = e^{0.567}, x = - e^{0.567}

Decimal Notation

x = 1.32776 \dots, x = - 1.32776 \dots

Solution steps

0.567 = ln (x^{2})

Apply log rules

e^{0.567} = x^{2}

Solve

e^{0.567} = x^{2} : x = e^{0.567}, x = - e^{0.567}

x = e^{0.567}, x = - e^{0.567}

2 lo g_{3} (x) - 1 = lo g_{3} (2 x - 3)

ln (x) + ln (x - 3) = ln (7 x)

lo g_{3} (x + 2) + lo g_{3} (x - 4) = 3

(ln (x - 1)) (ln (x - 1) - 2) = - 1

lo g_{10} (3 x) + lo g_{10} (5) = 1

What is the answer to 0.567=ln(x^2) ?
The answer to 0.567=ln(x^2) is x=sqrt(e^{0.567)},x=-sqrt(e^{0.567)}
Solve for x: 0.567=ln(x^2)
The solution is x=sqrt(e^{0.567)},x=-sqrt(e^{0.567)}