What is the answer to log_{10}(x^2-1)=2 ?

The answer to log_{10}(x^2-1)=2 is x=sqrt(101),x=-sqrt(101)

Solve for x: log_{10}(x^2-1)=2

The solution is x=sqrt(101),x=-sqrt(101)

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lo g_{10} (x^{2} - 1) = 2

x = 101, x = - 101

Decimal Notation

x = 10.04987 \dots, x = - 10.04987 \dots

Solution steps

lo g_{10} (x^{2} - 1) = 2

Apply log rules

x^{2} - 1 = 100

Solve

x^{2} - 1 = 100 : x = 101, x = - 101

x = 101, x = - 101

4 lo g_{10} (3 - 2 x) = - 1

lo g_{2} (lo g_{2} (x)) = 4

x, lo g_{4} (x y) = - 2

lo g_{3} (lo g_{5} (x)) = 1

2 ln (x) + 3 = 4

What is the answer to log_{10}(x^2-1)=2 ?
The answer to log_{10}(x^2-1)=2 is x=sqrt(101),x=-sqrt(101)
Solve for x: log_{10}(x^2-1)=2
The solution is x=sqrt(101),x=-sqrt(101)