What is the answer to log_{10}(9x)+log_{10}(x)=4 ?

The answer to log_{10}(9x)+log_{10}(x)=4 is x=10^{(4-2log_{10}(3))/2}

Solve for x: log_{10}(9x)+log_{10}(x)=4

The solution is x=10^{(4-2log_{10}(3))/2}

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lo g_{10} (9 x) + lo g_{10} (x) = 4

x = 1 0^{\frac{4 - 2 l o g _{10} ( 3 )}{2}}

Decimal Notation

x = 33.33333 \dots

Solution steps

lo g_{10} (9 x) + lo g_{10} (x) = 4

Apply log rules

x = 1 0^{\frac{4 - 2 l o g _{10} ( 3 )}{2}}

Verify Solutions:

x = 1 0^{\frac{4 - 2 l o g _{10} ( 3 )}{2}}

True

The solution is

x = 1 0^{\frac{4 - 2 l o g _{10} ( 3 )}{2}}

lo g_{10} (3 x) = 1.3

ln (4 x - 4) - 2 ln (x) = 0

lo g_{216} (x) = \frac{2}{3}

2 lo g_{10} (x) + 3 = 5 lo g_{10} (x)

ln (x + 2) + ln (x + 1) = 1

What is the answer to log_{10}(9x)+log_{10}(x)=4 ?
The answer to log_{10}(9x)+log_{10}(x)=4 is x=10^{(4-2log_{10}(3))/2}
Solve for x: log_{10}(9x)+log_{10}(x)=4
The solution is x=10^{(4-2log_{10}(3))/2}