What is the answer to ln(x+2)+ln(x+1)=1 ?

The answer to ln(x+2)+ln(x+1)=1 is x=(-3+sqrt(4e+1))/2

Solve for x: ln(x+2)+ln(x+1)=1

The solution is x=(-3+sqrt(4e+1))/2

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ln (x + 2) + ln (x + 1) = 1

x = \frac{- 3 + 4 e + 1}{2}

Decimal Notation

x = 0.22287 \dots

Solution steps

ln (x + 2) + ln (x + 1) = 1

Apply log rules

(x + 2) (x + 1) = e

Solve

(x + 2) (x + 1) = e : x = \frac{- 3 + 4 e + 1}{2}, x = \frac{- 3 - 4 e + 1}{2}

x = \frac{- 3 + 4 e + 1}{2}, x = \frac{- 3 - 4 e + 1}{2}

Verify Solutions:

x = \frac{- 3 + 4 e + 1}{2}

True

, x = \frac{- 3 - 4 e + 1}{2}

False

The solution is

x = \frac{- 3 + 4 e + 1}{2}

ln (x) = x - 1

ln (2 x) - ln (x - 1) = 15

ln (x) + ln (x + 3) = ln (10)

lo g_{2} (\frac{y}{3}) = 4

lo g_{9} (x + 4) - lo g_{9} (x) = 2

What is the answer to ln(x+2)+ln(x+1)=1 ?
The answer to ln(x+2)+ln(x+1)=1 is x=(-3+sqrt(4e+1))/2
Solve for x: ln(x+2)+ln(x+1)=1
The solution is x=(-3+sqrt(4e+1))/2