What are the solutions to the equation 4n^2-49=0 ?

The solutions to the equation 4n^2-49=0 are n= 7/2 ,n=-7/2

Find the zeros of 4n^2-49=0

The zeros of 4n^2-49=0 are n= 7/2 ,n=-7/2

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4 n^{2} - 49 = 0

n = \frac{7}{2}, n = - \frac{7}{2}

Solution steps

4 n^{2} - 49 = 0

Move

49

to the right side

4 n^{2} = 49

Divide both sides by

4

n^{2} = \frac{49}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

n = \frac{49}{4}, n = - \frac{49}{4}

\frac{49}{4} = \frac{7}{2}

- \frac{49}{4} = - \frac{7}{2}

n = \frac{7}{2}, n = - \frac{7}{2}

(x + 2)^{2} = 5

x^{2} + 11 x - 7 = 0

7 x - 12 x - 5 = - 45 + 15

4 x^{2} - 17 x + 4 = 0

0 \leq y \leq 1

What are the solutions to the equation 4n^2-49=0 ?
The solutions to the equation 4n^2-49=0 are n= 7/2 ,n=-7/2
Find the zeros of 4n^2-49=0
The zeros of 4n^2-49=0 are n= 7/2 ,n=-7/2