What is the answer to -2=log_{10}(2)-log_{10}(3+x) ?

The answer to -2=log_{10}(2)-log_{10}(3+x) is x=197

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-2=log_{10}(2)-log_{10}(3+x)

- 2 = lo g_{10} (2) - lo g_{10} (3 + x)

x = 197

Solution steps

- 2 = lo g_{10} (2) - lo g_{10} (3 + x)

Move

lo g_{10} (3 + x)

to the left side

- 2 + lo g_{10} (3 + x) = lo g_{10} (2)

Move

2

to the right side

lo g_{10} (3 + x) = lo g_{10} (2) + 2

Apply log rules

3 + x = 200

Solve

3 + x = 200 : x = 197

x = 197

Verify Solutions:

x = 197

True

The solution is

x = 197

lo g_{x} (\frac{1}{27}) = - 3

8 x^{2} = 64 x lo g_{2} (x)

2 lo g_{3} (x) + lo g_{3} (a) = 0

(ln (x))^{2} - 2 ln (x) - 3 = 0

x, ln (x) = ln (y) + c

What is the answer to -2=log_{10}(2)-log_{10}(3+x) ?
The answer to -2=log_{10}(2)-log_{10}(3+x) is x=197
Solve for x: -2=log_{10}(2)-log_{10}(3+x)
The solution is x=197