What is the answer to ln(x^2)=1 ?

The answer to ln(x^2)=1 is x=sqrt(e),x=-sqrt(e)

Solve for x: ln(x^2)=1

The solution is x=sqrt(e),x=-sqrt(e)

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ln (x^{2}) = 1

x = e, x = - e

Decimal Notation

x = 1.64872 \dots, x = - 1.64872 \dots

Solution steps

ln (x^{2}) = 1

Apply log rules

x^{2} = e

Solve

x^{2} = e : x = e, x = - e

x = e, x = - e

lo g_{9} (z) = \frac{1}{2}

lo g_{2} (x + 1) - lo g_{4} (x) = 1

lo g_{3} (x + 2) - lo g_{3} (2) = 1

ln (10 x + 5) - ln (4 - x) = ln (2)

lo g_{10} (x + 5) - 9 = lo g_{10} (3 x)

What is the answer to ln(x^2)=1 ?
The answer to ln(x^2)=1 is x=sqrt(e),x=-sqrt(e)
Solve for x: ln(x^2)=1
The solution is x=sqrt(e),x=-sqrt(e)