What is the answer to log_{3}(x+2)-log_{3}(2)=1 ?

The answer to log_{3}(x+2)-log_{3}(2)=1 is x=4

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log_{3}(x+2)-log_{3}(2)=1

lo g_{3} (x + 2) - lo g_{3} (2) = 1

x = 4

Solution steps

lo g_{3} (x + 2) - lo g_{3} (2) = 1

Move

lo g_{3} (2)

to the right side

lo g_{3} (x + 2) = 1 + lo g_{3} (2)

Apply log rules

x + 2 = 6

Solve

x + 2 = 6 : x = 4

x = 4

Verify Solutions:

x = 4

True

The solution is

x = 4

ln (10 x + 5) - ln (4 - x) = ln (2)

lo g_{10} (x + 5) - 9 = lo g_{10} (3 x)

lo g_{x} (64) = \frac{2}{3}

ln (4 x) - ln (x + 3) = ln (x^{2})

ln (x + 2) + ln (x - 3) = 0

What is the answer to log_{3}(x+2)-log_{3}(2)=1 ?
The answer to log_{3}(x+2)-log_{3}(2)=1 is x=4
Solve for x: log_{3}(x+2)-log_{3}(2)=1
The solution is x=4