What is the answer to ln(x+2)+ln(x-3)=0 ?

The answer to ln(x+2)+ln(x-3)=0 is x=(1+sqrt(29))/2

Solve for x: ln(x+2)+ln(x-3)=0

The solution is x=(1+sqrt(29))/2

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ln (x + 2) + ln (x - 3) = 0

x = \frac{1 + 29}{2}

Decimal Notation

x = 3.19258 \dots

Solution steps

ln (x + 2) + ln (x - 3) = 0

Apply log rules

(x + 2) (x - 3) = 1

Solve

(x + 2) (x - 3) = 1 : x = \frac{1 + 29}{2}, x = \frac{1 - 29}{2}

x = \frac{1 + 29}{2}, x = \frac{1 - 29}{2}

Verify Solutions:

x = \frac{1 + 29}{2}

True

, x = \frac{1 - 29}{2}

False

The solution is

x = \frac{1 + 29}{2}

lo g_{10} (3) = lo g_{10} (x + 1)

lo g_{b} (b^{2}) = 2

x, ln (x - y) = 0

0.61 = lo g_{10} (x)

3 lo g_{10} (2 x) = 4

What is the answer to ln(x+2)+ln(x-3)=0 ?
The answer to ln(x+2)+ln(x-3)=0 is x=(1+sqrt(29))/2
Solve for x: ln(x+2)+ln(x-3)=0
The solution is x=(1+sqrt(29))/2