What is the answer to log_{2}(7x+6)=3 ?

The answer to log_{2}(7x+6)=3 is x= 2/7

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log_{2}(7x+6)=3

lo g_{2} (7 x + 6) = 3

x = \frac{2}{7}

Decimal Notation

x = 0.28571 \dots

Solution steps

lo g_{2} (7 x + 6) = 3

Apply log rules

7 x + 6 = 8

Solve

7 x + 6 = 8 : x = \frac{2}{7}

x = \frac{2}{7}

lo g_{4} (- x) + lo g_{4} (x + 10) = 2

lo g_{10} (x^{2} - 15 x) = 2

lo g_{2} (\frac{x}{6}) = 8

ln (3 x - 15) = 9

lo g_{5} (y) = - 2