What is the answer to log_{2}(-6x-1)=-3 ?

The answer to log_{2}(-6x-1)=-3 is x=-3/16

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log_{2}(-6x-1)=-3

lo g_{2} (- 6 x - 1) = - 3

x = - \frac{3}{16}

Decimal Notation

x = - 0.1875

Solution steps

lo g_{2} (- 6 x - 1) = - 3

Apply log rules

- 6 x - 1 = \frac{1}{8}

Solve

- 6 x - 1 = \frac{1}{8} : x = - \frac{3}{16}

x = - \frac{3}{16}

0.66 = lo g_{10} (x)

x, ln (y) = 3 + ln (x)

lo g_{2} (2 x - 3) + lo g_{2} (x + 6) = 3

0 = 20 lo g_{10} (w)

lo g_{3} (2 x + 1) + lo g_{3} (x) = 1

What is the answer to log_{2}(-6x-1)=-3 ?
The answer to log_{2}(-6x-1)=-3 is x=-3/16
Solve for x: log_{2}(-6x-1)=-3
The solution is x=-3/16