What is the answer to solvefor x,ln(y)=3+ln(x) ?

The answer to solvefor x,ln(y)=3+ln(x) is x= 1/(e^3)y {y>0}

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solvefor x,ln(y)=3+ln(x)

solve for

x, ln (y) = 3 + ln (x)

x = \frac{1}{e ^{3}} y {y > 0}

Solution steps

ln (y) = 3 + ln (x)

Switch sides

3 + ln (x) = ln (y)

Move

3

to the right side

ln (x) = ln (y) - 3

Apply log rules

x = \frac{1}{e ^{3}} y

Verify Solutions:

x = \frac{1}{e ^{3}} y {y > 0}

The solution is

x = \frac{1}{e ^{3}} y {y > 0}

lo g_{2} (2 x - 3) + lo g_{2} (x + 6) = 3

0 = 20 lo g_{10} (w)

lo g_{3} (2 x + 1) + lo g_{3} (x) = 1

lo g_{2} (x) + lo g_{2} (x + 4) = 5

9 - 7 lo g_{10} (8 a + 7) = 2

What is the answer to solvefor x,ln(y)=3+ln(x) ?
The answer to solvefor x,ln(y)=3+ln(x) is x= 1/(e^3)y {y>0}