What are the solutions to the equation 8^2+2^2=x^2 ?

The solutions to the equation 8^2+2^2=x^2 are x=2sqrt(17),x=-2sqrt(17)

Find the zeros of 8^2+2^2=x^2

The zeros of 8^2+2^2=x^2 are x=2sqrt(17),x=-2sqrt(17)

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8^{2} + 2^{2} = x^{2}

x = 217, x = - 217

Decimal Notation

x = 8.24621 \dots, x = - 8.24621 \dots

Solution steps

8^{2} + 2^{2} = x^{2}

Switch sides

x^{2} = 8^{2} + 2^{2}

Simplify

8^{2} + 2^{2} : 68

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 68, x = - 68

68 = 217

- 68 = - 217

x = 217, x = - 217

\frac{\frac{z ^{2} + 20 z + 96}{2 z + 3}}{( z + 8 ) ^{2}}

125 + (x - y)^{3}

13 \geq 2 x - 3 \geq 5

y^{3} - 5 y^{2} + 6 y - 30

(x - 6)^{2} = - 7

What are the solutions to the equation 8^2+2^2=x^2 ?
The solutions to the equation 8^2+2^2=x^2 are x=2sqrt(17),x=-2sqrt(17)
Find the zeros of 8^2+2^2=x^2
The zeros of 8^2+2^2=x^2 are x=2sqrt(17),x=-2sqrt(17)