What is the answer to 3log_{3}(x)-log_{3}(7x)=1 ?

The answer to 3log_{3}(x)-log_{3}(7x)=1 is x=3^{(1+log_{3}(7))/2}

Solve for x: 3log_{3}(x)-log_{3}(7x)=1

The solution is x=3^{(1+log_{3}(7))/2}

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3 lo g_{3} (x) - lo g_{3} (7 x) = 1

x = 3^{\frac{1 + l o g _{3} ( 7 )}{2}}

Decimal Notation

x = 4.58257 \dots

Solution steps

3 lo g_{3} (x) - lo g_{3} (7 x) = 1

Apply log rules

x = 3^{\frac{1 + l o g _{3} ( 7 )}{2}}

Verify Solutions:

x = 3^{\frac{1 + l o g _{3} ( 7 )}{2}}

True

The solution is

x = 3^{\frac{1 + l o g _{3} ( 7 )}{2}}

lo g_{2} (3 x - 1) + lo g_{2} (x) = 1

ln (2 x - 7) = 0.5

lo g_{2} (x) = 24

lo g_{2} (x) + lo g_{2} (x + 7) = 3

lo g_{2} (x) = 32

What is the answer to 3log_{3}(x)-log_{3}(7x)=1 ?
The answer to 3log_{3}(x)-log_{3}(7x)=1 is x=3^{(1+log_{3}(7))/2}
Solve for x: 3log_{3}(x)-log_{3}(7x)=1
The solution is x=3^{(1+log_{3}(7))/2}