What is the answer to log_{2}(9x)-log_{2}(3)=3 ?

The answer to log_{2}(9x)-log_{2}(3)=3 is x= 8/3

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log_{2}(9x)-log_{2}(3)=3

lo g_{2} (9 x) - lo g_{2} (3) = 3

x = \frac{8}{3}

Decimal Notation

x = 2.66666 \dots

Solution steps

lo g_{2} (9 x) - lo g_{2} (3) = 3

Move

lo g_{2} (3)

to the right side

lo g_{2} (9 x) = 3 + lo g_{2} (3)

Apply log rules

9 x = 24

Solve

9 x = 24 : x = \frac{8}{3}

x = \frac{8}{3}

Verify Solutions:

x = \frac{8}{3}

True

The solution is

x = \frac{8}{3}

x, f^{- 1} (2) = 2 x + ln (x)

ln (x^{- 9}) = 6

ln (2) = - ln (2 x)

lo g_{5} (3 - 2 x) = lo g_{5} (- 3 x)

lo g_{10} (\frac{10 x}{3}) = 2

What is the answer to log_{2}(9x)-log_{2}(3)=3 ?
The answer to log_{2}(9x)-log_{2}(3)=3 is x= 8/3
Solve for x: log_{2}(9x)-log_{2}(3)=3
The solution is x= 8/3