What is the answer to ln(2x^2+7)=9 ?

The answer to ln(2x^2+7)=9 is x=sqrt((e^9-7)/2),x=-sqrt((e^9-7)/2)

Solve for x: ln(2x^2+7)=9

The solution is x=sqrt((e^9-7)/2),x=-sqrt((e^9-7)/2)

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ln (2 x^{2} + 7) = 9

x = \frac{e ^{9} - 7}{2}, x = - \frac{e ^{9} - 7}{2}

Decimal Notation

x = 63.62422 \dots, x = - 63.62422 \dots

Solution steps

ln (2 x^{2} + 7) = 9

Apply log rules

2 x^{2} + 7 = e^{9}

Solve

2 x^{2} + 7 = e^{9} : x = \frac{e ^{9} - 7}{2}, x = - \frac{e ^{9} - 7}{2}

x = \frac{e ^{9} - 7}{2}, x = - \frac{e ^{9} - 7}{2}

ln (e + x) = 1

5 ln (8 x + 10) - 16 = 19

lo g_{2} (x) + lo g_{2} (4 x) = 2

lo g_{x} (3) = lo g_{3} (9) x^{3}

lo g_{10} (x^{2} + 4 x - 2) = 1

What is the answer to ln(2x^2+7)=9 ?
The answer to ln(2x^2+7)=9 is x=sqrt((e^9-7)/2),x=-sqrt((e^9-7)/2)
Solve for x: ln(2x^2+7)=9
The solution is x=sqrt((e^9-7)/2),x=-sqrt((e^9-7)/2)