What is the answer to log_{6}(7x)+log_{6}(4)=4 ?

The answer to log_{6}(7x)+log_{6}(4)=4 is x= 324/7

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log_{6}(7x)+log_{6}(4)=4

lo g_{6} (7 x) + lo g_{6} (4) = 4

x = \frac{324}{7}

Decimal Notation

x = 46.28571 \dots

Solution steps

lo g_{6} (7 x) + lo g_{6} (4) = 4

Move

lo g_{6} (4)

to the right side

lo g_{6} (7 x) = 4 - lo g_{6} (4)

Apply log rules

7 x = 324

Solve

7 x = 324 : x = \frac{324}{7}

x = \frac{324}{7}

Verify Solutions:

x = \frac{324}{7}

True

The solution is

x = \frac{324}{7}

y, ln (y) = - ln (x) + c

lo g_{2} (x + 1) - lo g_{4} (x - 3) = 2

lo g_{x} (3) = - 2

lo g_{2} (4 x - 3) = 1

0.41 = ln (y)

What is the answer to log_{6}(7x)+log_{6}(4)=4 ?
The answer to log_{6}(7x)+log_{6}(4)=4 is x= 324/7
Solve for x: log_{6}(7x)+log_{6}(4)=4
The solution is x= 324/7