What is the answer to log_{10}(4x-3)+log_{10}(x)=0 ?

The answer to log_{10}(4x-3)+log_{10}(x)=0 is x=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{10}(4x-3)+log_{10}(x)=0

lo g_{10} (4 x - 3) + lo g_{10} (x) = 0

x = 1

Solution steps

lo g_{10} (4 x - 3) + lo g_{10} (x) = 0

Apply log rules

(4 x - 3) x = 1

Solve

(4 x - 3) x = 1 : x = 1, x = - \frac{1}{4}

x = 1, x = - \frac{1}{4}

Verify Solutions:

x = 1

True

, x = - \frac{1}{4}

False

The solution is

x = 1

2 ln (7 x) = 4

lo g_{4} (- x + 7) = lo g_{4} (2 x - 5)

lo g_{2} (x - 12) + lo g_{2} (x) = 6

lo g_{10} (x) = 0.1

lo g_{10} (x) = 0.7

What is the answer to log_{10}(4x-3)+log_{10}(x)=0 ?
The answer to log_{10}(4x-3)+log_{10}(x)=0 is x=1
Solve for x: log_{10}(4x-3)+log_{10}(x)=0
The solution is x=1