What is the answer to log_{2}(x-12)+log_{2}(x)=6 ?

The answer to log_{2}(x-12)+log_{2}(x)=6 is x=16

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log_{2}(x-12)+log_{2}(x)=6

lo g_{2} (x - 12) + lo g_{2} (x) = 6

x = 16

Solution steps

lo g_{2} (x - 12) + lo g_{2} (x) = 6

Apply log rules

(x - 12) x = 64

Solve

(x - 12) x = 64 : x = 16, x = - 4

x = 16, x = - 4

Verify Solutions:

x = 16

True

, x = - 4

False

The solution is

x = 16

lo g_{10} (x) = 0.1

lo g_{10} (x) = 0.7

lo g_{10} (x) = 0.8

lo g_{x} (2) = 10

lo g_{2} (x - 1) = - 1

What is the answer to log_{2}(x-12)+log_{2}(x)=6 ?
The answer to log_{2}(x-12)+log_{2}(x)=6 is x=16
Solve for x: log_{2}(x-12)+log_{2}(x)=6
The solution is x=16