What is the answer to log_{2}(x-1)=-1 ?

The answer to log_{2}(x-1)=-1 is x= 3/2

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log_{2}(x-1)=-1

lo g_{2} (x - 1) = - 1

x = \frac{3}{2}

Decimal Notation

x = 1.5

Solution steps

lo g_{2} (x - 1) = - 1

Apply log rules

x - 1 = \frac{1}{2}

Solve

x - 1 = \frac{1}{2} : x = \frac{3}{2}

x = \frac{3}{2}

ln (\frac{4 - x}{2 + 2 x}) = 0

lo g_{3} (x^{2}) - lo g_{3} (4 x) = 2

lo g_{10} (x + 1) = 1 + lo g_{10} (x)

lo g_{6} (2 x - 5) = lo g_{4} (6)

6 ln (2) - ln (4) = - ln (x)