What is the answer to ln((4-x)/(2+2x))=0 ?

The answer to ln((4-x)/(2+2x))=0 is x= 2/3

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ln((4-x)/(2+2x))=0

ln (\frac{4 - x}{2 + 2 x}) = 0

x = \frac{2}{3}

Decimal Notation

x = 0.66666 \dots

Solution steps

ln (\frac{4 - x}{2 + 2 x}) = 0

Apply log rules

\frac{4 - x}{2 + 2 x} = e^{0}

Multiply both sides by

2 + 2 x

\frac{4 - x}{2 + 2 x} (2 + 2 x) = e^{0} (2 + 2 x)

Simplify

4 - x = 2 + 2 x

Solve

4 - x = 2 + 2 x : x = \frac{2}{3}

x = \frac{2}{3}

Verify Solutions:

x = \frac{2}{3}

True

The solution is

x = \frac{2}{3}

lo g_{3} (x^{2}) - lo g_{3} (4 x) = 2

lo g_{10} (x + 1) = 1 + lo g_{10} (x)

lo g_{6} (2 x - 5) = lo g_{4} (6)

6 ln (2) - ln (4) = - ln (x)

lo g_{2} (lo g_{2} (x)) = 1

What is the answer to ln((4-x)/(2+2x))=0 ?
The answer to ln((4-x)/(2+2x))=0 is x= 2/3
Solve for x: ln((4-x)/(2+2x))=0
The solution is x= 2/3