What is the answer to log_{5}(x+12)-log_{5}(x+3)=1 ?

The answer to log_{5}(x+12)-log_{5}(x+3)=1 is x=-3/4

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log_{5}(x+12)-log_{5}(x+3)=1

lo g_{5} (x + 12) - lo g_{5} (x + 3) = 1

x = - \frac{3}{4}

Decimal Notation

x = - 0.75

Solution steps

lo g_{5} (x + 12) - lo g_{5} (x + 3) = 1

Add

lo g_{5} (x + 3)

to both sides

lo g_{5} (x + 12) - lo g_{5} (x + 3) + lo g_{5} (x + 3) = 1 + lo g_{5} (x + 3)

Simplify

lo g_{5} (x + 12) = 1 + lo g_{5} (x + 3)

Apply log rules

x + 12 = 5 (x + 3)

Solve

x + 12 = 5 (x + 3) : x = - \frac{3}{4}

x = - \frac{3}{4}

Verify Solutions:

x = - \frac{3}{4}

True

The solution is

x = - \frac{3}{4}

11.9 = - lo g_{10} (x)

lo g_{6} (4) + lo g_{6} (x) = 2

x + lo g_{10} (x - 9) = 1

lo g_{6} (x) + lo g_{6} (x + 16) = 2

lo g_{10} (2 x + 1) = lo g_{10} (x + 6)

What is the answer to log_{5}(x+12)-log_{5}(x+3)=1 ?
The answer to log_{5}(x+12)-log_{5}(x+3)=1 is x=-3/4
Solve for x: log_{5}(x+12)-log_{5}(x+3)=1
The solution is x=-3/4