What is the answer to log_{2}(-3x+3)=4 ?

The answer to log_{2}(-3x+3)=4 is x=-13/3

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log_{2}(-3x+3)=4

lo g_{2} (- 3 x + 3) = 4

x = - \frac{13}{3}

Decimal Notation

x = - 4.33333 \dots

Solution steps

lo g_{2} (- 3 x + 3) = 4

Apply log rules

- 3 x + 3 = 16

Solve

- 3 x + 3 = 16 : x = - \frac{13}{3}

x = - \frac{13}{3}

lo g_{5} (x^{2}) = - 2

ln (5 x + e) = 1

ln (x - 1) = lo g_{81} (3)

lo g_{9} (8 - x) + lo g_{9} (8 - x) = 1

ln (x^{2}) - 1 = 3

What is the answer to log_{2}(-3x+3)=4 ?
The answer to log_{2}(-3x+3)=4 is x=-13/3
Solve for x: log_{2}(-3x+3)=4
The solution is x=-13/3