What is the answer to log_{5}(sqrt(x^2+1))=1 ?

The answer to log_{5}(sqrt(x^2+1))=1 is x=2sqrt(6),x=-2sqrt(6)

Solve for x: log_{5}(sqrt(x^2+1))=1

The solution is x=2sqrt(6),x=-2sqrt(6)

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lo g_{5} (x^{2} + 1) = 1

x = 26, x = - 26

Decimal Notation

x = 4.89897 \dots, x = - 4.89897 \dots

Solution steps

lo g_{5} (x^{2} + 1) = 1

Apply log rules

x^{2} + 1 = 5

Solve

x^{2} + 1 = 5 : x = 26, x = - 26

x = 26, x = - 26

3 lo g_{2} (x + 5) - 3 = 12

2 lo g_{6} (5) = lo g_{6} (x)

ln (3 x) + ln (2 x) = 6

lo g_{\frac{1}{2}} (x) = - 5

lo g_{\frac{1}{2}} (x) = - 4

What is the answer to log_{5}(sqrt(x^2+1))=1 ?
The answer to log_{5}(sqrt(x^2+1))=1 is x=2sqrt(6),x=-2sqrt(6)
Solve for x: log_{5}(sqrt(x^2+1))=1
The solution is x=2sqrt(6),x=-2sqrt(6)