What is the answer to 3log_{2}(x+5)-3=12 ?

The answer to 3log_{2}(x+5)-3=12 is x=27

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3log_{2}(x+5)-3=12

3 lo g_{2} (x + 5) - 3 = 12

x = 27

Solution steps

3 lo g_{2} (x + 5) - 3 = 12

Move

3

to the right side

3 lo g_{2} (x + 5) = 15

Divide both sides by

3

lo g_{2} (x + 5) = 5

Apply log rules

x + 5 = 32

Solve

x + 5 = 32 : x = 27

x = 27

Verify Solutions:

x = 27

True

The solution is

x = 27

2 lo g_{6} (5) = lo g_{6} (x)

ln (3 x) + ln (2 x) = 6

lo g_{\frac{1}{2}} (x) = - 5

lo g_{\frac{1}{2}} (x) = - 4

2 lo g_{4} (x - 2) + 1 = 7

What is the answer to 3log_{2}(x+5)-3=12 ?
The answer to 3log_{2}(x+5)-3=12 is x=27
Solve for x: 3log_{2}(x+5)-3=12
The solution is x=27