What is the answer to log_{2}(8)+log_{2}(x+1)=4 ?

The answer to log_{2}(8)+log_{2}(x+1)=4 is x=1

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log_{2}(8)+log_{2}(x+1)=4

lo g_{2} (8) + lo g_{2} (x + 1) = 4

x = 1

Solution steps

lo g_{2} (8) + lo g_{2} (x + 1) = 4

Move

lo g_{2} (8)

to the right side

lo g_{2} (x + 1) = 4 - lo g_{2} (8)

Apply log rules

x + 1 = 2

Solve

x + 1 = 2 : x = 1

x = 1

Verify Solutions:

x = 1

True

The solution is

x = 1

lo g_{7} (- x) - lo g_{7} (6 - x) = 1

lo g_{3} (3 x - 1) = 2

n lo g_{a} (x) = lo g_{a} (x^{n})

lo g_{2} ((r + 13)^{2}) = 6

- lo g_{10} (x) = 10

What is the answer to log_{2}(8)+log_{2}(x+1)=4 ?
The answer to log_{2}(8)+log_{2}(x+1)=4 is x=1
Solve for x: log_{2}(8)+log_{2}(x+1)=4
The solution is x=1