What is the answer to log_{10}(4)+2log_{10}(x)=6 ?

The answer to log_{10}(4)+2log_{10}(x)=6 is x=10^{(6-2log_{10}(2))/2}

Solve for x: log_{10}(4)+2log_{10}(x)=6

The solution is x=10^{(6-2log_{10}(2))/2}

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lo g_{10} (4) + 2 lo g_{10} (x) = 6

x = 1 0^{\frac{6 - 2 l o g _{10} ( 2 )}{2}}

Decimal Notation

x = 499.99999 \dots

Solution steps

lo g_{10} (4) + 2 lo g_{10} (x) = 6

Move

lo g_{10} (4)

to the right side

2 lo g_{10} (x) = 6 - lo g_{10} (4)

Divide both sides by

2

lo g_{10} (x) = \frac{6 - lo g _{10} ( 4 )}{2}

Apply log rules

x = 1 0^{\frac{6 - 2 l o g _{10} ( 2 )}{2}}

Verify Solutions:

x = 1 0^{\frac{6 - 2 l o g _{10} ( 2 )}{2}}

True

The solution is

x = 1 0^{\frac{6 - 2 l o g _{10} ( 2 )}{2}}

lo g_{5} (y) = 4 - 4 lo g_{y} (5)

lo g_{10} (x + 4) + lo g_{10} (x) = 9

4 ln (2 x + 9) + 5 = 29

lo g_{x} (9 x - 20) = 2

x, ln (x^{2}) = 4

What is the answer to log_{10}(4)+2log_{10}(x)=6 ?
The answer to log_{10}(4)+2log_{10}(x)=6 is x=10^{(6-2log_{10}(2))/2}
Solve for x: log_{10}(4)+2log_{10}(x)=6
The solution is x=10^{(6-2log_{10}(2))/2}