What is the answer to log_{6}(x-5)+log_{6}(x)=2 ?

The answer to log_{6}(x-5)+log_{6}(x)=2 is x=9

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log_{6}(x-5)+log_{6}(x)=2

lo g_{6} (x - 5) + lo g_{6} (x) = 2

x = 9

Solution steps

lo g_{6} (x - 5) + lo g_{6} (x) = 2

Apply log rules

(x - 5) x = 36

Solve

(x - 5) x = 36 : x = 9, x = - 4

x = 9, x = - 4

Verify Solutions:

x = 9

True

, x = - 4

False

The solution is

x = 9

lo g_{6} (x - 1) + lo g_{6} (x) = 1

a = - lo g_{10} (x)

\frac{1}{2} ln (x + 3) - ln (x) = 0

x^{2} ln (x) - 49 ln (x) = 0

y, ln (y) = - x^{2}

What is the answer to log_{6}(x-5)+log_{6}(x)=2 ?
The answer to log_{6}(x-5)+log_{6}(x)=2 is x=9
Solve for x: log_{6}(x-5)+log_{6}(x)=2
The solution is x=9