What is the answer to (log_{3}(x)-2)log_{3}(x)=0 ?

The answer to (log_{3}(x)-2)log_{3}(x)=0 is x=9,x=1

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(log_{3}(x)-2)log_{3}(x)=0

(lo g_{3} (x) - 2) lo g_{3} (x) = 0

x = 9, x = 1

Solution steps

(lo g_{3} (x) - 2) lo g_{3} (x) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

lo g_{3} (x) - 2 = 0 or lo g_{3} (x) = 0

Solve

lo g_{3} (x) - 2 = 0 : x = 9

Solve

lo g_{3} (x) = 0 : x = 1

Verify Solutions:

x = 9

True

, x = 1

True

The solutions are

x = 9, x = 1

lo g_{5} (x) = - 4

lo g_{8} (2 N - 3) = lo g_{8} (4 - N)

5 lo g_{2} (2 x) = 20

ln (x + 10) + ln (x - 4) = 2 ln (x)

2 ln (x - 6) = - 4

What is the answer to (log_{3}(x)-2)log_{3}(x)=0 ?
The answer to (log_{3}(x)-2)log_{3}(x)=0 is x=9,x=1
Solve for x: (log_{3}(x)-2)log_{3}(x)=0
The solution is x=9,x=1