What is the answer to 4=(ln(2x))/(ln(4x)) ?

The answer to 4=(ln(2x))/(ln(4x)) is x= 1/(e^{\frac{7ln(2)){3}}}

Solve for x: 4=(ln(2x))/(ln(4x))

The solution is x= 1/(e^{\frac{7ln(2)){3}}}

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4 = \frac{ln ( 2 x )}{ln ( 4 x )}

x = \frac{1}{e ^{\frac{7 l n ( 2 )}{3}}}

Decimal Notation

x = 0.19842 \dots

Solution steps

4 = \frac{ln ( 2 x )}{ln ( 4 x )}

Multiply both sides by

ln (4 x)

4 ln (4 x) = \frac{ln ( 2 x )}{ln ( 4 x )} ln (4 x)

Simplify

4 ln (4 x) = ln (2 x)

Apply log rules

x = \frac{1}{e ^{\frac{7 l n ( 2 )}{3}}}

Verify Solutions:

x = \frac{1}{e ^{\frac{7 l n ( 2 )}{3}}}

True

The solution is

x = \frac{1}{e ^{\frac{7 l n ( 2 )}{3}}}

2 lo g_{2} (x) = 4

t, x = ln (t)

lo g_{2} (x^{2}) = 4

lo g_{4} (x) - lo g_{16} (x - 4) = 1

lo g_{10} (c) = 2

What is the answer to 4=(ln(2x))/(ln(4x)) ?
The answer to 4=(ln(2x))/(ln(4x)) is x= 1/(e^{\frac{7ln(2)){3}}}
Solve for x: 4=(ln(2x))/(ln(4x))
The solution is x= 1/(e^{\frac{7ln(2)){3}}}