What is the answer to log_{4}(x)-log_{16}(x-4)=1 ?

The answer to log_{4}(x)-log_{16}(x-4)=1 is x=8

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log_{4}(x)-log_{16}(x-4)=1

lo g_{4} (x) - lo g_{16} (x - 4) = 1

x = 8

Solution steps

lo g_{4} (x) - lo g_{16} (x - 4) = 1

Apply log rules

x^{2} = 16 (x - 4)

Solve

x^{2} = 16 (x - 4) : x = 8

x = 8

Verify Solutions:

x = 8

True

The solution is

x = 8

lo g_{10} (c) = 2

lo g_{10} (y) = 5

lo g_{4} (x + 2) = 2

a, lo g_{10} (a) = 2 lo g_{10} (b)

lo g_{2} (7 x + 2) = 1

What is the answer to log_{4}(x)-log_{16}(x-4)=1 ?
The answer to log_{4}(x)-log_{16}(x-4)=1 is x=8
Solve for x: log_{4}(x)-log_{16}(x-4)=1
The solution is x=8