What is the answer to solvefor a,log_{10}(a)=2log_{10}(b) ?

The answer to solvefor a,log_{10}(a)=2log_{10}(b) is a=b^2 {b>0}

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solvefor a,log_{10}(a)=2log_{10}(b)

solve for

a, lo g_{10} (a) = 2 lo g_{10} (b)

a = b^{2} {b > 0}

Solution steps

lo g_{10} (a) = 2 lo g_{10} (b)

Apply log rules

a = b^{2}

Verify Solutions:

a = b^{2} {b > 0}

The solution is

a = b^{2} {b > 0}

lo g_{2} (7 x + 2) = 1

ln (- x) + ln (10) = 5

ln (x - 2 e) + ln (x - 3 e) = 2

ln (3 x - 11) = 9

ln (3 x - 11) = 3

What is the answer to solvefor a,log_{10}(a)=2log_{10}(b) ?
The answer to solvefor a,log_{10}(a)=2log_{10}(b) is a=b^2 {b>0}