What is the answer to 3ln(4x+5)-19=-7 ?

The answer to 3ln(4x+5)-19=-7 is x=(e^4-5)/4

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3ln(4x+5)-19=-7

3 ln (4 x + 5) - 19 = - 7

x = \frac{e ^{4} - 5}{4}

Decimal Notation

x = 12.39953 \dots

Solution steps

3 ln (4 x + 5) - 19 = - 7

Move

19

to the right side

3 ln (4 x + 5) = 12

Divide both sides by

3

ln (4 x + 5) = 4

Apply log rules

4 x + 5 = e^{4}

Solve

4 x + 5 = e^{4} : x = \frac{e ^{4} - 5}{4}

x = \frac{e ^{4} - 5}{4}

Verify Solutions:

x = \frac{e ^{4} - 5}{4}

True

The solution is

x = \frac{e ^{4} - 5}{4}

lo g_{3} (x + 2) + lo g_{3} (x) = 1

lo g_{27} (x) = - \frac{2}{3}

5 - lo g_{4} (8) = lo g_{4} (x)

7.3 = - lo g_{10} (x)

lo g_{3} (4 x + 1) = 4

What is the answer to 3ln(4x+5)-19=-7 ?
The answer to 3ln(4x+5)-19=-7 is x=(e^4-5)/4
Solve for x: 3ln(4x+5)-19=-7
The solution is x=(e^4-5)/4