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Popular >

ln(d)=aln(p)+b

Solution

ln (d) = a ln (p) + b

Solution

p = e^{\frac{l n ( d ) - b}{a}}

Solution steps

ln (d) = a ln (p) + b

Switch sides

a ln (p) + b = ln (d)

Move

b

to the right side

a ln (p) = ln (d) - b

Divide both sides by

a

ln (p) = \frac{ln ( d ) - b}{a}

Apply log rules

p = e^{\frac{l n ( d ) - b}{a}}

Popular Examples

log_{10}(x)=-15.4223

lo g_{10} (x) = - 15.4223

log_{4}(x+9)=2-log_{4}(x-6)

lo g_{4} (x + 9) = 2 - lo g_{4} (x - 6)

2log_{2}(x)-log_{2}(x+8)=2

2 lo g_{2} (x) - lo g_{2} (x + 8) = 2

14 = lo g_{2} (m)

lo g_{5} (x - 1) = 1

Frequently Asked Questions (FAQ)

What is the answer to ln(d)=aln(p)+b ?
The answer to ln(d)=aln(p)+b is p=e^{(ln(d)-b)/a}