What is the answer to log_{6}(4x)+2log_{6}(3)=0 ?

The answer to log_{6}(4x)+2log_{6}(3)=0 is x= 1/36

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log_{6}(4x)+2log_{6}(3)=0

lo g_{6} (4 x) + 2 lo g_{6} (3) = 0

x = \frac{1}{36}

Decimal Notation

x = 0.02777 \dots

Solution steps

lo g_{6} (4 x) + 2 lo g_{6} (3) = 0

Move

2 lo g_{6} (3)

to the right side

lo g_{6} (4 x) = - 2 lo g_{6} (3)

Apply log rules

4 x = \frac{1}{9}

Solve

4 x = \frac{1}{9} : x = \frac{1}{36}

x = \frac{1}{36}

Verify Solutions:

x = \frac{1}{36}

True

The solution is

x = \frac{1}{36}

lo g_{10} (x) = - 2.3

lo g_{10} (5) + 3 lo g_{10} (x) = 3

x, ln (y) = ln (x) + 2

lo g_{10} (x) - lo g_{10} (x - 5) = 1

x, ln (x) = y^{2}

What is the answer to log_{6}(4x)+2log_{6}(3)=0 ?
The answer to log_{6}(4x)+2log_{6}(3)=0 is x= 1/36
Solve for x: log_{6}(4x)+2log_{6}(3)=0
The solution is x= 1/36