What is the answer to solvefor x,ln(y)=ln(x)+2 ?

The answer to solvefor x,ln(y)=ln(x)+2 is x= 1/(e^2)y {y>0}

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solvefor x,ln(y)=ln(x)+2

solve for

x, ln (y) = ln (x) + 2

x = \frac{1}{e ^{2}} y {y > 0}

Solution steps

ln (y) = ln (x) + 2

Switch sides

ln (x) + 2 = ln (y)

Move

2

to the right side

ln (x) = ln (y) - 2

Apply log rules

x = \frac{1}{e ^{2}} y

Verify Solutions:

x = \frac{1}{e ^{2}} y {y > 0}

The solution is

x = \frac{1}{e ^{2}} y {y > 0}

lo g_{10} (x) - lo g_{10} (x - 5) = 1

x, ln (x) = y^{2}

lo g_{10} (5 x) = 4

5 ln (6 x + 9) + 20 = 5

lo g_{2} (x + 1) + lo g_{2} (x - 3) = 5

What is the answer to solvefor x,ln(y)=ln(x)+2 ?
The answer to solvefor x,ln(y)=ln(x)+2 is x= 1/(e^2)y {y>0}