What is the answer to log_{10}(2)+log_{10}(x+1)=1 ?

The answer to log_{10}(2)+log_{10}(x+1)=1 is x=4

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log_{10}(2)+log_{10}(x+1)=1

lo g_{10} (2) + lo g_{10} (x + 1) = 1

x = 4

Solution steps

lo g_{10} (2) + lo g_{10} (x + 1) = 1

Move

lo g_{10} (2)

to the right side

lo g_{10} (x + 1) = 1 - lo g_{10} (2)

Apply log rules

x + 1 = 5

Solve

x + 1 = 5 : x = 4

x = 4

Verify Solutions:

x = 4

True

The solution is

x = 4

2 lo g_{2} (x) - lo g_{2} (x + 5) = 4

lo g_{0.4} (x) = - 3

lo g_{7} (4 x) + 3 lo g_{7} (5) = 5

lo g_{4} (x) = \frac{1}{4}

ln (x^{2} + 7 x + 12) - ln (x + 4) = 0

What is the answer to log_{10}(2)+log_{10}(x+1)=1 ?
The answer to log_{10}(2)+log_{10}(x+1)=1 is x=4
Solve for x: log_{10}(2)+log_{10}(x+1)=1
The solution is x=4