What is the answer to (1+ln(x))/(x^2)=0 ?

The answer to (1+ln(x))/(x^2)=0 is x= 1/e

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(1+ln(x))/(x^2)=0

\frac{1 + ln ( x )}{x ^{2}} = 0

x = \frac{1}{e}

Decimal Notation

x = 0.36787 \dots

Solution steps

\frac{1 + ln ( x )}{x ^{2}} = 0

Multiply both sides by

x^{2}

1 + ln (x) = 0

Move

1

to the right side

ln (x) = - 1

Apply log rules

x = \frac{1}{e}

Verify Solutions:

x = \frac{1}{e}

True

The solution is

x = \frac{1}{e}

lo g_{5} (7 - x) = lo g_{5} (1 - x) + 2

5 = ln (- 5 x + 3)

15.328 = - 1.451 ln (x) + 24.036

3 lo g_{x} (3) + lo g_{3} (x) = 4

lo g_{x - 4} (4) = \frac{3}{2}

What is the answer to (1+ln(x))/(x^2)=0 ?
The answer to (1+ln(x))/(x^2)=0 is x= 1/e
Solve for x: (1+ln(x))/(x^2)=0
The solution is x= 1/e