What are the solutions to the equation x^2+20x+94=0 ?

The solutions to the equation x^2+20x+94=0 are x=-10+sqrt(6),x=-10-sqrt(6)

Find the zeros of x^2+20x+94=0

The zeros of x^2+20x+94=0 are x=-10+sqrt(6),x=-10-sqrt(6)

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x^{2} + 20 x + 94 = 0

x = - 10 + 6, x = - 10 - 6

Decimal Notation

x = - 7.55051 \dots, x = - 12.44948 \dots

Solution steps

x^{2} + 20 x + 94 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot 94}{2 \cdot 1}

2 0^{2} - 4 \cdot 1 \cdot 94 = 26

x_{1, 2} = \frac{- 20 \pm 2 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 20 + 2 6}{2 \cdot 1}, x_{2} = \frac{- 20 - 2 6}{2 \cdot 1}

x = \frac{- 20 + 2 6}{2 \cdot 1} : - 10 + 6

x = \frac{- 20 - 2 6}{2 \cdot 1} : - 10 - 6

The solutions to the quadratic equation are:

x = - 10 + 6, x = - 10 - 6

2 z + 4 (z + 1) = 5 - 0 z

64 v^{4} - 225 w^{10}

36 x^{2} y - 9 y

12 5^{\frac{- 3}{4}} \cdot 5^{\frac{- 3}{4}}

- 5 (x + 6) - 10 = 10

What are the solutions to the equation x^2+20x+94=0 ?
The solutions to the equation x^2+20x+94=0 are x=-10+sqrt(6),x=-10-sqrt(6)
Find the zeros of x^2+20x+94=0
The zeros of x^2+20x+94=0 are x=-10+sqrt(6),x=-10-sqrt(6)