What is the answer to ln(x)+ln(x+4)=3 ?

The answer to ln(x)+ln(x+4)=3 is x=(-4+sqrt(16+4e^3))/2

Solve for x: ln(x)+ln(x+4)=3

The solution is x=(-4+sqrt(16+4e^3))/2

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ln (x) + ln (x + 4) = 3

x = \frac{- 4 + 16 + 4 e ^{3}}{2}

Decimal Notation

x = 2.90770 \dots

Solution steps

ln (x) + ln (x + 4) = 3

Apply log rules

x (x + 4) = e^{3}

Solve

x (x + 4) = e^{3} : x = \frac{- 4 + 16 + 4 e ^{3}}{2}, x = \frac{- 4 - 16 + 4 e ^{3}}{2}

x = \frac{- 4 + 16 + 4 e ^{3}}{2}, x = \frac{- 4 - 16 + 4 e ^{3}}{2}

Verify Solutions:

x = \frac{- 4 + 16 + 4 e ^{3}}{2}

True

, x = \frac{- 4 - 16 + 4 e ^{3}}{2}

False

The solution is

x = \frac{- 4 + 16 + 4 e ^{3}}{2}

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lo g_{10} (x) = 6.6

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What is the answer to ln(x)+ln(x+4)=3 ?
The answer to ln(x)+ln(x+4)=3 is x=(-4+sqrt(16+4e^3))/2
Solve for x: ln(x)+ln(x+4)=3
The solution is x=(-4+sqrt(16+4e^3))/2