What is the answer to ln(3x)+ln(2x)=9 ?

The answer to ln(3x)+ln(2x)=9 is x=e^{(9-ln(6))/2}

Solve for x: ln(3x)+ln(2x)=9

The solution is x=e^{(9-ln(6))/2}

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ln (3 x) + ln (2 x) = 9

x = e^{\frac{9 - l n ( 6 )}{2}}

Decimal Notation

x = 36.74933 \dots

Solution steps

ln (3 x) + ln (2 x) = 9

Apply log rules

x = e^{\frac{9 - l n ( 6 )}{2}}

Verify Solutions:

x = e^{\frac{9 - l n ( 6 )}{2}}

True

The solution is

x = e^{\frac{9 - l n ( 6 )}{2}}

ln (e) + 4 ln (x) = ln (e^{5})

lo g_{10} (x) = 6.6

lo g_{2} (x) = 6 - lo g_{2} (x + 12)

lo g_{6} (3 - m) + lo g_{6} (- m - 2) = 1

x^{l n (4)} + 4^{l n (x)} = 32

What is the answer to ln(3x)+ln(2x)=9 ?
The answer to ln(3x)+ln(2x)=9 is x=e^{(9-ln(6))/2}
Solve for x: ln(3x)+ln(2x)=9
The solution is x=e^{(9-ln(6))/2}