What is the answer to 0.912=ln(x^2) ?

The answer to 0.912=ln(x^2) is x=sqrt(e^{0.912)},x=-sqrt(e^{0.912)}

Solve for x: 0.912=ln(x^2)

The solution is x=sqrt(e^{0.912)},x=-sqrt(e^{0.912)}

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0.912 = ln (x^{2})

x = e^{0.912}, x = - e^{0.912}

Decimal Notation

x = 1.57775 \dots, x = - 1.57775 \dots

Solution steps

0.912 = ln (x^{2})

Apply log rules

e^{0.912} = x^{2}

Solve

e^{0.912} = x^{2} : x = e^{0.912}, x = - e^{0.912}

x = e^{0.912}, x = - e^{0.912}

lo g_{a} (2048) = 11

ln (3) + ln (2 x + 5) = 2 ln (x + 2)

lo g_{20} (x) = 1 + lo g_{20} (10)

2 lo g_{10} (x + 5) - lo g_{3} (9) = 2

ln (5 x + 4) = 3

What is the answer to 0.912=ln(x^2) ?
The answer to 0.912=ln(x^2) is x=sqrt(e^{0.912)},x=-sqrt(e^{0.912)}
Solve for x: 0.912=ln(x^2)
The solution is x=sqrt(e^{0.912)},x=-sqrt(e^{0.912)}