What is the answer to 3ln(7x-4)-11=1 ?

The answer to 3ln(7x-4)-11=1 is x=(e^4+4)/7

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3ln(7x-4)-11=1

3 ln (7 x - 4) - 11 = 1

x = \frac{e ^{4} + 4}{7}

Decimal Notation

x = 8.37116 \dots

Solution steps

3 ln (7 x - 4) - 11 = 1

Move

11

to the right side

3 ln (7 x - 4) = 12

Divide both sides by

3

ln (7 x - 4) = 4

Apply log rules

7 x - 4 = e^{4}

Solve

7 x - 4 = e^{4} : x = \frac{e ^{4} + 4}{7}

x = \frac{e ^{4} + 4}{7}

Verify Solutions:

x = \frac{e ^{4} + 4}{7}

True

The solution is

x = \frac{e ^{4} + 4}{7}

5 = lo g_{10} (x) + lo g_{10} (x - 1)

2 x - e^{2} lo g_{e} (x) = 0

lo g_{5} (x + 2) + lo g_{5} (x - 2) = 1

lo g_{8} (2 n - 3) = lo g_{8} (4 - n)

2 7^{l o g_{9} (x)} = x^{1.5}

What is the answer to 3ln(7x-4)-11=1 ?
The answer to 3ln(7x-4)-11=1 is x=(e^4+4)/7
Solve for x: 3ln(7x-4)-11=1
The solution is x=(e^4+4)/7