What is the answer to 27^{log_{9}(x)}=x^{1.5} ?

The answer to 27^{log_{9}(x)}=x^{1.5} is x>0

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27^{log_{9}(x)}=x^{1.5}

2 7^{l o g_{9} (x)} = x^{1.5}

x > 0

Solution steps

2 7^{l o g_{9} (x)} = x^{1.5}

Apply log rules

x = x

Both sides are equal

True for all x

Verify Solutions:

x > 0

True

The solution is

x > 0

lo g_{3^{2}} ((x - 1)^{2}) = - 1

lo g_{2} (x) = 3 - lo g_{2} (3 x + 10)

lo g_{2} (x^{2} - 5 x + 14) = 3

lo g_{5} (x + 7) = - lo g_{5} (x + 3) + 1

lo g_{2} (x^{3}) = lo g_{8} (x)

What is the answer to 27^{log_{9}(x)}=x^{1.5} ?
The answer to 27^{log_{9}(x)}=x^{1.5} is x>0
Solve for x: 27^{log_{9}(x)}=x^{1.5}
The solution is x>0