What is the answer to log_{3^2}((x-1)^2)=-1 ?

The answer to log_{3^2}((x-1)^2)=-1 is x= 4/3 ,x= 2/3

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log_{3^2}((x-1)^2)=-1

lo g_{3^{2}} ((x - 1)^{2}) = - 1

x = \frac{4}{3}, x = \frac{2}{3}

Decimal Notation

x = 1.33333 \dots, x = 0.66666 \dots

Solution steps

lo g_{3^{2}} ((x - 1)^{2}) = - 1

Apply log rules

(x - 1)^{2} = \frac{1}{9}

Solve

(x - 1)^{2} = \frac{1}{9} : x = \frac{4}{3}, x = \frac{2}{3}

x = \frac{4}{3}, x = \frac{2}{3}

lo g_{2} (x) = 3 - lo g_{2} (3 x + 10)

lo g_{2} (x^{2} - 5 x + 14) = 3

lo g_{5} (x + 7) = - lo g_{5} (x + 3) + 1

lo g_{2} (x^{3}) = lo g_{8} (x)

lo g_{2} (x) + lo g_{4} (x) = 1

What is the answer to log_{3^2}((x-1)^2)=-1 ?
The answer to log_{3^2}((x-1)^2)=-1 is x= 4/3 ,x= 2/3
Solve for x: log_{3^2}((x-1)^2)=-1
The solution is x= 4/3 ,x= 2/3